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Syntax
Table.PositionOfAny(
table as table,
rows as list,
optional occurrence as nullable number,
optional equationCriteria as any
) as any
About
Returns the row(s) position(s) from the table of the first occurrence of the list of rows. Returns -1 if no occurrence is found.
table: The input table.rows: The list of rows in the table to find the positions of.occurrence: [Optional] Specifies which occurrences of the row to return.- `equationCriteria: [Optional] Controls the comparison between the table rows.
Example 1
Find the position of the first occurrence of [a = 2, b = 4] or [a = 6, b = 8] in the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}).
Usage
Table.PositionOfAny(
Table.FromRecords({
[a = 2, b = 4],
[a = 1, b = 4],
[a = 2, b = 4],
[a = 1, b = 4]
}),
{
[a = 2, b = 4],
[a = 6, b = 8]
}
)
Output
0
Example 2
Find the position of all the occurrences of [a = 2, b = 4] or [a = 6, b = 8] in the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}.
Usage
Table.PositionOfAny(
Table.FromRecords({
[a = 2, b = 4],
[a = 6, b = 8],
[a = 2, b = 4],
[a = 1, b = 4]
}),
{
[a = 2, b = 4],
[a = 6, b = 8]
},
Occurrence.All
)
Output
{0, 1, 2}